LT1213/LT1214
典型PERFOR一个CE特征
5V小信号响应
3V
20mV/DIV
50ns/DIV
V
S
= 5V
A
V
= 1
1213/14 G25
±15V
小信号响应
20mV/DIV
V
S
=
±15V
A
V
= 1
50ns/DIV
1213/14 G28
5V沉降
500mV/DIV
输出步（ V）
2V/DIV
100ns/DIV
V
S
= 5V
A
V
= 1
1213/14 G31
ü W
5V大信号响应
3V
5V大信号响应
0V
200ns/DIV
V
S
= 5V
A
V
= 1
1213/14 G26
0V
200ns/DIV
V
S
= 5V
A
V
= –1
R
F
= R
G
= 1k
C
F
= 20pF的
1213/14 G27
±15V
大信号响应
±15V
大信号响应
10V
10V
0V
0V
–10V
–10V
V
S
=
±15V
A
V
= 1
1s/DIV
1213/14 G29
V
S
=
±15V
A
V
= –1
R
F
= R
G
= 1k
1s/DIV
1213/14 G30
±15V
解决
10
8
6
4
2
0
–2
–4
–6
–8
1213/14 G32
建立时间0.01％
与输出步骤
V
S
=
±15V
反相
同相
250V/DIV
1mV/DIV
反相
同相
V
S
=
±15V
A
V
= –1
200ns/DIV
–10
300 400 500 600 700 800 900 1000 1100
稳定时间（纳秒）
1213/14 G33
11
