
AD8132 -典型性能特征
2
CF
348
0.5
1
0
增益 - 分贝
V
S
= 3V
0.4
V
S
= 5V
0.3
0.2
增益 - 分贝
V
S
如图所示
G=1
V
O, DM
= 0.2V P-P
R
L, DM
= 499
V
S
= 3V
V
S
= 5V
348
49.9
0.1 F
499
–1
–2
–3
V
S
如图所示
G=1
V
O, DM
= 0.2V P-P
R
L, DM
= 499
1
10
V
S
=
5V
0.1
0.0
–0.1
–0.2
–0.3
–0.4
–0.5
V
S
=
5V
24.9
348
348
CF
–4
–5
100
1k
1
10
100
1k
频率 - 兆赫
频率 - 兆赫
TPC 1.基本测试电路,G = 1
TPC 2.小信号频率
响应
TPC 3. 0.1 dB平坦度与频率的关系;
C
F
= 0 pF的
0.2
0.1
0.0
增益 - 分贝
增益 - 分贝
3
V
S
= 3V
V
S
= 5V
2
1
V
S
= 3V
V
S
= 5V
2
V
S
=
5V
1
0
V
S
= 3V
V
S
= 5V
V
S
=
5V
增益 - 分贝
–0.1
–0.2
–0.3
–0.4
–0.5
V
S
=
5V
0
–1
–2
–3
–4
V
S
如图所示
G=1
V
O, DM
= 2V, P-P FOR V
S
= 5V, 5V
V
O, DM
= 1V P-P FOR V
S
= 3V
R
L, DM
= 499
1
10
100
1k
V
S
= 3V
–1
–2
–3
–4
–5
V
S
= 3V
V
S
如图所示
G=1
V
O, DM
= 0.2V P-P
R
L, DM
= 499
1
10
100
1k
V
S
如图所示
G=1
V
O, DM
= 2V, P-P FOR V
S
= 5V, 5V
V
O, DM
= 1V P-P FOR V
S
= 3V
R
L, DM
= 499
–5
1
10
100
1k
频率 - 兆赫
频率 - 兆赫
频率 - 兆赫
TPC 4. 0.1 dB平坦度与频率的关系;
C
F
= 0.5 pF的
TPC 5.大信号频率
响应;
F
= 0 pF的
TPC 6.大信号频率
响应;
F
= 0.5 pF的
3
2
1
+85 C
+25 C
3
2
1
增益 - 分贝
100
R
F
= 499
R
F
= 348
10
增益 - 分贝
0
–1
–2
–3
–4
V
S
= 5V
G=1
V
O, DM
= 2V峰 - 峰值
R
L, DM
= 499
R
F
如图所示
1
10
100
1k
R
F
= 249
–40 C
–1
–2
–3
–4
–5
1
V
S
= 5V
G=1
V
O, DM
= 2V峰 - 峰值
R
L, DM
= 499
温度显示
10
100
1k
阻抗
0
1
V
S
= 5V
V
S
=
0.1
1
10
频率 - 兆赫
100
5V
–5
频率 - 兆赫
频率 - 兆赫
TPC 7.大信号响应 -
温度
TPC 8.大信号频率
响应与
F
TPC 9.闭环单端
Z
OUT
与频率的关系; G = 1
–6–
第0版